What is (d^2)/(dy^2)(xye^{(-x+3y)}) ?

The answer to (d^2)/(dy^2)(xye^{(-x+3y)}) is x(9e^{-x+3y}y+6e^{-x+3y})

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(d^2)/(dy^2)(xye^{(-x+3y)})

\frac{d ^{2}}{d y ^{2}} (x y e^{(- x + 3 y)})

x (9 e^{- x + 3 y} y + 6 e^{- x + 3 y})

Solution steps

\frac{d ^{2}}{d y ^{2}} (x y e^{(- x + 3 y)})

\frac{d}{d y} (x y e^{- x + 3 y}) = x (e^{- x + 3 y} + 3 e^{- x + 3 y} y)

= \frac{d}{d y} (x (e^{- x + 3 y} + 3 e^{- x + 3 y} y))

\frac{d}{d y} (x (e^{- x + 3 y} + 3 e^{- x + 3 y} y)) = x (9 e^{- x + 3 y} y + 6 e^{- x + 3 y})

= x (9 e^{- x + 3 y} y + 6 e^{- x + 3 y})

(0.4) (2)

\int \frac{x}{x ^{2} - 4} d x

\frac{\partial}{\partial x} (7 tan (x y))

n \to \infty lim (1)

y = 5 x - x^{2}, y = 3 x^{2} + x

What is (d^2)/(dy^2)(xye^{(-x+3y)}) ?
The answer to (d^2)/(dy^2)(xye^{(-x+3y)}) is x(9e^{-x+3y}y+6e^{-x+3y})