What is the first (sin(2t))^' ?

The first (sin(2t))^' is cos(2t)*2

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(sin(2t))^'

(sin (2 t))^{^{'}}

cos (2 t) \cdot 2

Solution steps

(sin (2 t))^{'}

Apply the chain rule:

cos (2 t) (2 t)^{'}

= cos (2 t) (2 t)^{'}

(2 t)^{'} = 2

= cos (2 t) \cdot 2

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