What is (\partial)/(\partial y)(sin(y)sin(x)) ?

The answer to (\partial)/(\partial y)(sin(y)sin(x)) is sin(x)cos(y)

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(\partial)/(\partial y)(sin(y)sin(x))

\frac{\partial}{\partial y} (sin (y) sin (x))

sin (x) cos (y)

Solution steps

\frac{\partial}{\partial y} (sin (y) sin (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (x) \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= sin (x) cos (y)

x + y^{2} = 12, x + y = 0

\int tan^{5} (2 x) sec^{4} (2 x) d x

\int \frac{1}{t ^{2} - 4 t + 29} d t

\int 4 - t d t

\int_{0}^{2} (x^{2} - 2)^{4} x d x

What is (\partial)/(\partial y)(sin(y)sin(x)) ?
The answer to (\partial)/(\partial y)(sin(y)sin(x)) is sin(x)cos(y)