What is the integral of 1/(sqrt(x+3)) ?

The integral of 1/(sqrt(x+3)) is 2sqrt(x+3)+C

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integral of 1/(sqrt(x+3))

\int \frac{1}{x + 3} d x

2 x + 3 + C

Solution steps

\int \frac{1}{x + 3} d x

Apply u-substitution

: \int 2 d u

= \int 2 d u

Integral of a constant:

\int a d x = a x

= 2 u

Substitute back

u = x + 3

= 2 x + 3

Add a constant to the solution

= 2 x + 3 + C

\frac{2 t e ^{- 3 t}}{5} - 3 t sin (t)

\int x (x^{2} - 4 x) d x

\int e^{5 x} x^{2} d x

\int \frac{4 x ^{2}}{x ^{3} + 4} d x

\int t^{2} e^{- t} d t

What is the integral of 1/(sqrt(x+3)) ?
The integral of 1/(sqrt(x+3)) is 2sqrt(x+3)+C