What is the d/(dt)(sqrt(2)t) ?

The d/(dt)(sqrt(2)t) is square root of 2

What is the first d/(dt)(sqrt(2)t) ?

The first d/(dt)(sqrt(2)t) is square root of 2

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\frac{d}{d t} (2 t)

2

Solution steps

\frac{d}{d t} (2 t)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d t}{d t}

Apply the common derivative:

\frac{d t}{d t} = 1

= 2 \cdot 1

Simplify

= 2

\frac{d y}{d x} = y^{2} e^{x} sin (3 x), y (0) = 1

f (x) = \frac{x ^{2} - 4}{x - 4}

\frac{\partial}{\partial x} (e^{(- x^{2} - y^{2})})

x = 4 t^{2} - 3 t + 11

\frac{d}{d x} (sin^{2} (x) + sin (x))

What is the d/(dt)(sqrt(2)t) ?
The d/(dt)(sqrt(2)t) is square root of 2
What is the first d/(dt)(sqrt(2)t) ?
The first d/(dt)(sqrt(2)t) is square root of 2