What is the tangent of f(x)=2x^2,\at x=5 ?

The tangent of f(x)=2x^2,\at x=5 is y=20x-50

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2x^2,\at x=5

tangent of

f (x) = 2 x^{2}, at x = 5

y = 20 x - 50

Solution steps

Find the tangent point:

(5, 50)

Find the slope of

f (x) = 2 x^{2} : \frac{df ( x )}{d x} = 4 x

Compute the slope of

f (x) = 2 x^{2}

x = 5 : m = 20

Find the line with slope m=

20

and passing through

(5, 50) : y = 20 x - 50

y = 20 x - 50

\int 7 cos^{2} (x) sin (2 x) d x

\int t^{2} cos (n t) d t

\int \frac{- x}{x} d x

s \to 0 lim (s \cdot \frac{k}{s \cdot ( \frac{s}{5} + 1 ) \cdot ( \frac{s}{50} + 1 )})

\frac{\partial}{\partial x} (x^{3} y^{5} + 9 x^{5} y)

What is the tangent of f(x)=2x^2,\at x=5 ?
The tangent of f(x)=2x^2,\at x=5 is y=20x-50