What is the solution for (dy)/(dx)+y-4cos(x)=0 ?

The solution for (dy)/(dx)+y-4cos(x)=0 is y=2(sin(x)+cos(x))+(c_{1})/(e^x)

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(dy)/(dx)+y-4cos(x)=0

\frac{d y}{d x} + y - 4 cos (x) = 0

y = 2 (sin (x) + cos (x)) + \frac{c _{1}}{e ^{x}}

Solution steps

\frac{d y}{d x} + y - 4 cos (x) = 0

Solve linear ODE:

y = 2 (sin (x) + cos (x)) + \frac{c _{1}}{e ^{x}}

y = 2 (sin (x) + cos (x)) + \frac{c _{1}}{e ^{x}}

\int_{0}^{5} \frac{1}{x ^{\frac{17}{18}}} d x

\int v e^{uv} d u

f (x) = (5 - 2 x) (3 x - 1)^{3}

\int \frac{x + 3}{3 x ^{2} - 6 x + 8} d x

What is the solution for (dy)/(dx)+y-4cos(x)=0 ?
The solution for (dy)/(dx)+y-4cos(x)=0 is y=2(sin(x)+cos(x))+(c_{1})/(e^x)