What is area y=e^x,y=e^{-3x},x=ln(6) ?

The answer to area y=e^x,y=e^{-3x},x=ln(6) is 3025/648

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=e^x,y=e^{-3x},x=ln(6)

area

y = e^{x}, y = e^{- 3 x}, x = ln (6)

\frac{3025}{648}

Decimal Notation

4.66820 \dots

Solution steps

Apply the area formula:

\int_{0}^{l n (6)} e^{x} - e^{- 3 x} d x

Solve

\int_{0}^{l n (6)} e^{x} - e^{- 3 x} d x : \frac{3025}{648}

The area is:

= \frac{3025}{648}

\frac{d y}{d t} = t^{2} + 13 t^{2} y

\int (e^{x} + x cos (y)) d y

\int_{3}^{6} \frac{x}{x ^{2} + 4 x + 13} d x

\int \frac{x ^{4}}{x ^{10} - 1} d x

f (x) = \frac{7}{x - 6}

What is area y=e^x,y=e^{-3x},x=ln(6) ?
The answer to area y=e^x,y=e^{-3x},x=ln(6) is 3025/648