What is the first derivative of x^2+1 ?

The first derivative of x^2+1 is 2x

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derivative of x^2+1

derivative of

x^{2} + 1

2 x

Solution steps

\frac{d}{d x} (x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

Simplify

= 2 x

x \to 0 - lim (\frac{sin ( 2 x )}{x})

\int \frac{x ^{3} - 3 x ^{2} + 5 x - 3}{x - 1} d x

y = 3 x - x^{2}, y = - 5 x

f (x) = 3 x + 1, at x = 5

\frac{d}{d x} (2 e^{6 x})