What is the limit as x approaches 1 of ln(x^{1/2}) ?

The limit as x approaches 1 of ln(x^{1/2}) is 0

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limit as x approaches 1 of ln(x^{1/2})

x \to 1 lim (ln (x^{\frac{1}{2}}))

0

Solution steps

x \to 1 lim (ln (x^{\frac{1}{2}}))

Plug in the value

x = 1

= ln (1^{\frac{1}{2}})

Simplify

ln (1^{\frac{1}{2}}) : 0

= 0

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What is the limit as x approaches 1 of ln(x^{1/2}) ?
The limit as x approaches 1 of ln(x^{1/2}) is 0