What is the solution for x^2dx+2ydy=0 ?

The solution for x^2dx+2ydy=0 is y=sqrt(-(x^3)/3+c_{1)},y=-sqrt(-(x^3)/3+c_{1)}

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x^2dx+2ydy=0

x^{2} d x + 2 y d y = 0

y = - \frac{x ^{3}}{3} + c_{1}, y = - - \frac{x ^{3}}{3} + c_{1}

Solution steps

x^{2} d x + 2 y d y = 0

Solve separable ODE:

y = - \frac{x ^{3}}{3} + c_{1}, y = - - \frac{x ^{3}}{3} + c_{1}

y = - \frac{x ^{3}}{3} + c_{1}, y = - - \frac{x ^{3}}{3} + c_{1}

\frac{s}{s ^{2} + 6 s + 34}

\frac{\partial}{\partial y} (\frac{( x + y )}{x - y})

\int \frac{1}{sin ( x ) cos ( x ) + cos ^{2} ( x )} d x

\int \frac{cos ( x )}{1 - sin ( x )} d x

n = 0 \sum \infty \frac{1}{( 4 n ^{2} - 1 )}

What is the solution for x^2dx+2ydy=0 ?
The solution for x^2dx+2ydy=0 is y=sqrt(-(x^3)/3+c_{1)},y=-sqrt(-(x^3)/3+c_{1)}