What is the tangent of f(x)=x^3-15x,(1,-14) ?

The tangent of f(x)=x^3-15x,(1,-14) is y=-12x-2

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tangent of f(x)=x^3-15x,(1,-14)

tangent of

f (x) = x^{3} - 15 x, (1, - 14)

y = - 12 x - 2

Solution steps

Find the slope of

f (x) = x^{3} - 15 x : \frac{df ( x )}{d x} = 3 x^{2} - 15

Compute the slope of

f (x) = x^{3} - 15 x

(1, - 14) : m = - 12

Find the line with slope m=

- 12

and passing through

(1, - 14) : y = - 12 x - 2

y = - 12 x - 2

\frac{d}{d x} (\frac{10}{x})

\int \frac{y ln ( x )}{x} d x

\frac{1}{5 x}, at x = 9

\frac{1}{( ( 3 - 2 x ) )}

\frac{5 x + 2}{6 x - 4}

What is the tangent of f(x)=x^3-15x,(1,-14) ?
The tangent of f(x)=x^3-15x,(1,-14) is y=-12x-2