What is the limit as x approaches-1 of (x-1)/(x+1) ?

The limit as x approaches-1 of (x-1)/(x+1) is diverges

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limit as x approaches-1 of (x-1)/(x+1)

x \to - 1 lim (\frac{x - 1}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{x - 1}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x - 1}{x + 1}) = - \infty

x \to - 1 - lim (\frac{x - 1}{x + 1}) = \infty

= diverges

\int sin^{5} (\frac{x}{2}) d x

\frac{d}{d x} (x^{2} sin (ln (x)))

x \to 0 lim (5 - 2 x^{2})

x \to 3 lim (2 x^{- 1})

\frac{d y}{d x} = \frac{1}{4} y cos^{2} (y)

What is the limit as x approaches-1 of (x-1)/(x+1) ?
The limit as x approaches-1 of (x-1)/(x+1) is diverges