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Popular >

d/(dt)(sin(3ln(t)-e^{t^2}))

Solution

\frac{d}{d t} (sin (3 ln (t) - e^{t^{2}}))

Solution

cos (3 ln (t) - e^{t^{2}}) (\frac{3}{t} - e^{t^{2}} \cdot 2 t)

Solution steps

\frac{d}{d t} (sin (3 ln (t) - e^{t^{2}}))

Apply the chain rule:

cos (3 ln (t) - e^{t^{2}}) \frac{d}{d t} (3 ln (t) - e^{t^{2}})

= cos (3 ln (t) - e^{t^{2}}) \frac{d}{d t} (3 ln (t) - e^{t^{2}})

\frac{d}{d t} (3 ln (t) - e^{t^{2}}) = \frac{3}{t} - e^{t^{2}} \cdot 2 t

= cos (3 ln (t) - e^{t^{2}}) (\frac{3}{t} - e^{t^{2}} \cdot 2 t)

Popular Examples

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\int \frac{x ^{5} + 1}{x ^{3} - 3 x ^{2} - 10 x} d x

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\frac{d}{d x} (e^{x} x + 7 e^{x})

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\int (e^{x} - 3)^{2} d x

area 10x^4-10x^2,9x^2 area

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Frequently Asked Questions (FAQ)

What is the d/(dt)(sin(3ln(t)-e^{t^2})) ?
The d/(dt)(sin(3ln(t)-e^{t^2})) is cos(3ln(t)-e^{t^2})(3/t-e^{t^2}*2t)
What is the first d/(dt)(sin(3ln(t)-e^{t^2})) ?
The first d/(dt)(sin(3ln(t)-e^{t^2})) is cos(3ln(t)-e^{t^2})(3/t-e^{t^2}*2t)