What is the solution for (dx)/(dy)=sin(x+y) ?

The solution for (dx)/(dy)=sin(x+y) is x=2arctan((-2-y-c_{1})/(y+c_{1)})+2pin-y

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(dx)/(dy)=sin(x+y)

\frac{d x}{d y} = sin (x + y)

x = 2 arctan (\frac{- 2 - y - c _{1}}{y + c _{1}}) + 2 πn - y

Solution steps

\frac{d x}{d y} = sin (x + y)

Solve using substitution:

x = 2 arctan (\frac{- 2 - y - c _{1}}{y + c _{1}}) + 2 πn - y

x = 2 arctan (\frac{- 2 - y - c _{1}}{y + c _{1}}) + 2 πn - y

(2 x - 1)^{2} \cdot ln (2 x - 1)

(0.4) (6.8)

y^{^{'}} = - a y

\frac{d}{d x} (x^{a} y^{1 - a})

x \to 0 lim (arctan (5 x))

What is the solution for (dx)/(dy)=sin(x+y) ?
The solution for (dx)/(dy)=sin(x+y) is x=2arctan((-2-y-c_{1})/(y+c_{1)})+2pin-y