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Popular >

area f(x)= 1/x ,[1,2]

Solution

area

f (x) = \frac{1}{x}, [1, 2]

Solution

ln (2)

+1

Decimal Notation

0.69314 \dots

Solution steps

Apply the area formula:

\int_{1}^{2} \frac{1}{∣ x ∣} d x

Solve

\int_{1}^{2} \frac{1}{∣ x ∣} d x : ln (2)

The area is:

= ln (2)

Popular Examples

integral from-5 to 0 of 2^{1-x}

\int_{- 5}^{0} 2^{1 - x} d x

tangent of y=(6x)/(x^2+1)tangent of

y = \frac{6 x}{x ^{2} + 1}

(\partial)/(\partial x)(xsin(2y))

\frac{\partial}{\partial x} (x sin (2 y))

derivative of f(x)=(x^2+3)(x^2-4x)derivative of

f (x) = (x^{2} + 3) (x^{2} - 4 x)

integral of (5x^2+7x-11)/(x^2)

\int \frac{5 x ^{2} + 7 x - 11}{x ^{2}} d x

Frequently Asked Questions (FAQ)

What is area f(x)= 1/x ,[1,2] ?
The answer to area f(x)= 1/x ,[1,2] is ln(2)