What is (\partial)/(\partial x)(x^2y^4) ?

The answer to (\partial)/(\partial x)(x^2y^4) is 2xy^4

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(\partial)/(\partial x)(x^2y^4)

\frac{\partial}{\partial x} (x^{2} y^{4})

2 x y^{4}

Solution steps

\frac{\partial}{\partial x} (x^{2} y^{4})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{4} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{4} \cdot 2 x^{2 - 1}

Simplify

= 2 x y^{4}

x \to 0 lim (\frac{5 x ^{2}}{x})

\frac{\partial}{\partial x} (\frac{x}{4 x ^{2} + 9 y ^{2}})

y = \frac{x + 5}{x ^{3} + x - 9}

f (x) = \frac{6 x + x ^{2}}{( 3 + x ) ^{2}}

\int \frac{3 - 18 x}{1 - 9 x ^{2}} d x

What is (\partial)/(\partial x)(x^2y^4) ?
The answer to (\partial)/(\partial x)(x^2y^4) is 2xy^4