What is the tangent of 3x^2+3x ?

The tangent of 3x^2+3x is y=(6a_{0}+3)x-3a_{0}^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 3x^2+3x

tangent of

3 x^{2} + 3 x

y = (6 a_{0} + 3) x - 3 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} + 3 a_{0})

Find the slope of

y = 3 x^{2} + 3 x : \frac{d y}{d x} = 6 x + 3

Compute the slope of

y = 3 x^{2} + 3 x

x = a_{0} : m = 6 a_{0} + 3

Find the line with slope m=

6 a_{0} + 3

and passing through

(a_{0}, 3 a_{0}^{2} + 3 a_{0}) : y = (6 a_{0} + 3) x - 3 a_{0}^{2}

y = (6 a_{0} + 3) x - 3 a_{0}^{2}

\frac{d}{d t} (\frac{1}{t ^{2} + 1})

f (x) = x + 1 - ln (x), at x = 0.5

(t^{2} + x^{2}) d t + (t x) d x = 0

\int_{0}^{π} \frac{1}{x} d x

\frac{d}{d x} (ln (x x^{2} - 7))

What is the tangent of 3x^2+3x ?
The tangent of 3x^2+3x is y=(6a_{0}+3)x-3a_{0}^2