What is the limit as x approaches 0-of 7/(1+e^{1/x)} ?

The limit as x approaches 0-of 7/(1+e^{1/x)} is 7

Popular >

limit as x approaches 0-of 7/(1+e^{1/x)}

x \to 0 - lim (\frac{7}{1 + e ^{\frac{1}{x}}})

7

Solution steps

x \to 0 - lim (\frac{7}{1 + e ^{\frac{1}{x}}})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 7 \cdot x \to 0 - lim (\frac{1}{1 + e ^{\frac{1}{x}}})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= 7 \cdot \frac{lim _{x \to 0 -} ( 1 )}{lim _{x \to 0 -} ( 1 + e ^{\frac{1}{x}} )}

x \to 0 - lim (1) = 1

x \to 0 - lim (1 + e^{\frac{1}{x}}) = 1

= 7 \cdot \frac{1}{1}

Simplify

= 7

\frac{\partial}{\partial x} (x \cdot cos (y) \cdot sin (z))

\int 16 sin^{6} (x) cos^{3} (x) d x

\frac{d}{d x} (\frac{e ^{x}}{x + 4})

\frac{\partial}{\partial z} (x yz + x y^{3} + y z^{3} + z x^{3})

x \to - 2 lim (x + 5)

What is the limit as x approaches 0-of 7/(1+e^{1/x)} ?
The limit as x approaches 0-of 7/(1+e^{1/x)} is 7