What is the integral from 1 to 9 of sqrt(u+2) ?

The integral from 1 to 9 of sqrt(u+2) is (22sqrt(11))/3-2sqrt(3)

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integral from 1 to 9 of sqrt(u+2)

\int_{1}^{9} u + 2 d u

\frac{22 11}{3} - 23

Decimal Notation

20.85781 \dots

Solution steps

\int_{1}^{9} u + 2 d u

Apply u-substitution

: \int_{3}^{11} v d v

= \int_{3}^{11} v d v

Apply the Power Rule

: [\frac{2}{3} v^{\frac{3}{2}}]_{3}^{11}

= [\frac{2}{3} v^{\frac{3}{2}}]_{3}^{11}

Compute the boundaries:

\frac{22 11}{3} - 23

= \frac{22 11}{3} - 23

\int \frac{x ^{4} + 3 x ^{2} + 1}{x ^{5} + 5 x ^{3} + 5 x} d x

\int e^{\frac{- x}{2}} d x

cot (x^{5})

5^{3^{x^{2}}}

x^{2} y^{^{'}} + 2 x y = 5 cos^{2} (x)

What is the integral from 1 to 9 of sqrt(u+2) ?
The integral from 1 to 9 of sqrt(u+2) is (22sqrt(11))/3-2sqrt(3)