What is the derivative of 9pir^2 ?

The derivative of 9pir^2 is 18pir

What is the first derivative of 9pir^2 ?

The first derivative of 9pir^2 is 18pir

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derivative of

9 π r^{2}

18 π r

Solution steps

\frac{d}{d r} (9 π r^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 π \frac{d}{d r} (r^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 π 2 r^{2 - 1}

Simplify

= 18 π r

\int \frac{6 x - 1}{x ^{3} ( 2 x - 1 )} d x

\int \frac{x}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}} d x

y = 18 x

\frac{\partial}{\partial x} (- x - x^{3} sin (2 y))

\int \frac{9 t - 7}{t + 1} d t

What is the derivative of 9pir^2 ?
The derivative of 9pir^2 is 18pir
What is the first derivative of 9pir^2 ?
The first derivative of 9pir^2 is 18pir