What is the derivative of sqrt(x^4-1) ?

The derivative of sqrt(x^4-1) is (2x^3)/(sqrt(x^4-1))

What is the first derivative of sqrt(x^4-1) ?

The first derivative of sqrt(x^4-1) is (2x^3)/(sqrt(x^4-1))

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\frac{d}{d x} (x^{4} - 1)

\frac{2 x ^{3}}{x ^{4} - 1}

Solution steps

\frac{d}{d x} (x^{4} - 1)

Apply the chain rule:

\frac{1}{2 x ^{4} - 1} \frac{d}{d x} (x^{4} - 1)

= \frac{1}{2 x ^{4} - 1} \frac{d}{d x} (x^{4} - 1)

\frac{d}{d x} (x^{4} - 1) = 4 x^{3}

= \frac{1}{2 x ^{4} - 1} \cdot 4 x^{3}

Simplify

\frac{1}{2 x ^{4} - 1} \cdot 4 x^{3} : \frac{2 x ^{3}}{x ^{4} - 1}

= \frac{2 x ^{3}}{x ^{4} - 1}

\frac{d}{d x} (\frac{3 x}{x - 2})

\int \frac{1}{16 e ^{- 4 x} + e ^{4 x}} d x

sin ((π x)^{4})

\int_{2}^{4} (x^{2} + 2)^{3} x d x

\int (a - x)^{3} d x

What is the derivative of sqrt(x^4-1) ?
The derivative of sqrt(x^4-1) is (2x^3)/(sqrt(x^4-1))
What is the first derivative of sqrt(x^4-1) ?
The first derivative of sqrt(x^4-1) is (2x^3)/(sqrt(x^4-1))