What is the tangent of f(x)=3x^2-2x,\at x=-1 ?

The tangent of f(x)=3x^2-2x,\at x=-1 is y=-8x-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3x^2-2x,\at x=-1

tangent of

f (x) = 3 x^{2} - 2 x, at x = - 1

y = - 8 x - 3

Solution steps

Find the tangent point:

(- 1, 5)

Find the slope of

f (x) = 3 x^{2} - 2 x : \frac{df ( x )}{d x} = 6 x - 2

Compute the slope of

f (x) = 3 x^{2} - 2 x

x = - 1 : m = - 8

Find the line with slope m=

- 8

and passing through

(- 1, 5) : y = - 8 x - 3

y = - 8 x - 3

\frac{d}{d t} (0. 9^{t})

x \to 0 lim (\frac{x - 9}{x - 1})

\frac{d y}{d t} = \frac{1}{y}

n = 0 \sum \infty (- \frac{2}{3} x)^{n}

\frac{d}{d x} (\frac{1}{2 x} + \frac{1}{3 x ^{\frac{2}{3}}})

What is the tangent of f(x)=3x^2-2x,\at x=-1 ?
The tangent of f(x)=3x^2-2x,\at x=-1 is y=-8x-3