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Popular >

3x^'+6x=4

Solution

3 x^{^{'}} + 6 x = 4

Solution

x = - \frac{e ^{- 2 t - c_{1}}}{3} + \frac{2}{3}

Solution steps

3 x^{'} (t) + 6 x = 4

Solve separable ODE:

x = - \frac{e ^{- 2 t - c_{1}}}{3} + \frac{2}{3}

x = - \frac{e ^{- 2 t - c_{1}}}{3} + \frac{2}{3}

Popular Examples

(rdθ)/(dr)=θ^2+1

\frac{r d θ}{d r} = θ^{2} + 1

tangent of f(x)=5-x^2,\at x=1 tangent of

f (x) = 5 - x^{2}, at x = 1

derivative of x^2-7 derivative of

x^{2} - 7

limit as x approaches 4+of 3/(x-4)

x \to 4 + lim (\frac{3}{x - 4})

2 y^{^{'}} - y^{2} + 4 = 0

Frequently Asked Questions (FAQ)

What is the solution for 3x^'+6x=4 ?
The solution for 3x^'+6x=4 is x=-(e^{-2t-c_{1}})/3+2/3