What is the derivative of 3xe^{3x} ?

The derivative of 3xe^{3x} is 3(e^{3x}+3e^{3x}x)

What is the first derivative of 3xe^{3x} ?

The first derivative of 3xe^{3x} is 3(e^{3x}+3e^{3x}x)

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derivative of

3 x e^{3 x}

3 (e^{3 x} + 3 e^{3 x} x)

Solution steps

\frac{d}{d x} (3 x e^{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x e^{3 x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{3 x}

= 3 (\frac{d x}{d x} e^{3 x} + \frac{d}{d x} (e^{3 x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= 3 (1 \cdot e^{3 x} + e^{3 x} \cdot 3 x)

Simplify

= 3 (e^{3 x} + 3 e^{3 x} x)

\frac{d}{d y} (y e^{x y})

6 \frac{d y}{d t} - 2 y = t y^{4}, y (0) = - 2

\frac{d}{d t} (7 sin (t))

\frac{t}{( t - 3 ) ^{2}}

\frac{d}{d x} (sin^{x} (x))

What is the derivative of 3xe^{3x} ?
The derivative of 3xe^{3x} is 3(e^{3x}+3e^{3x}x)
What is the first derivative of 3xe^{3x} ?
The first derivative of 3xe^{3x} is 3(e^{3x}+3e^{3x}x)