What is the sum from n=1 to infinity of (2n+1)/n ?

The sum from n=1 to infinity of (2n+1)/n is diverges

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sum from n=1 to infinity of (2n+1)/n

n = 1 \sum \infty \frac{2 n + 1}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{2 n + 1}{n}

Apply Series Divergence Test:

diverges

= diverges

\frac{5 x + 1}{x ^{2} - 3}

y^{^{''}} + 4 y^{^{'}} + 5 y = 34 e^{2 t}, y (0) = 1, y^{^{'}} (0) = 2

y^{^{''}} = 32 e^{2 t}, y (0) = 3, y^{^{'}} (0) = 8

\int_{a}^{b} \frac{1}{b - a}

16 y^{^{''}} + 24 y^{^{'}} + 9 y = 0, y (2) = 4, y^{^{'}} (- 2) = - 3

What is the sum from n=1 to infinity of (2n+1)/n ?
The sum from n=1 to infinity of (2n+1)/n is diverges