What is the derivative of-3cos(-3x) ?

The derivative of-3cos(-3x) is 9sin(3x)

What is the first derivative of-3cos(-3x) ?

The first derivative of-3cos(-3x) is 9sin(3x)

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derivative of

- 3 cos (- 3 x)

9 sin (3 x)

Solution steps

\frac{d}{d x} (- 3 cos (- 3 x))

Simplify

- 3 cos (- 3 x) : - 3 cos (3 x)

= \frac{d}{d x} (- 3 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 3 (- sin (3 x) \cdot 3)

Simplify

= 9 sin (3 x)

\frac{d}{d x} (x - 1 - ln (x))

x^{2} (1 - y) \frac{d y}{d x} + y^{2} (1 + x) = 0

\frac{d y}{d t} - 2 y = 8 e^{4 t}

\int \frac{1}{27} e^{3 x} d x

x \to 0 + lim (\frac{9 x}{sin ( x )})

What is the derivative of-3cos(-3x) ?
The derivative of-3cos(-3x) is 9sin(3x)
What is the first derivative of-3cos(-3x) ?
The first derivative of-3cos(-3x) is 9sin(3x)