What is (\partial)/(\partial y)(x^2*ln(y)) ?

The answer to (\partial)/(\partial y)(x^2*ln(y)) is (x^2)/y

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(\partial)/(\partial y)(x^2*ln(y))

\frac{\partial}{\partial y} (x^{2} \cdot ln (y))

\frac{x ^{2}}{y}

Solution steps

\frac{\partial}{\partial y} (x^{2} ln (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (ln (y))

Apply the common derivative:

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= x^{2} \frac{1}{y}

Simplify

x^{2} \frac{1}{y} : \frac{x ^{2}}{y}

= \frac{x ^{2}}{y}

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What is (\partial)/(\partial y)(x^2*ln(y)) ?
The answer to (\partial)/(\partial y)(x^2*ln(y)) is (x^2)/y