What is inverse oflaplace-(1.25)/(s+2) ?

The answer to inverse oflaplace-(1.25)/(s+2) is -1.25e^{-2t}

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inverse oflaplace-(1.25)/(s+2)

inverse laplace

- \frac{1.25}{s + 2}

- 1.25 e^{- 2 t}

Solution steps

L^{- 1} {- \frac{1.25}{s + 2}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - L^{- 1} {\frac{1.25}{s + 2}}

L^{- 1} {\frac{1.25}{s + 2}} : 1.25 e^{- 2 t}

= - 1.25 e^{- 2 t}

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What is inverse oflaplace-(1.25)/(s+2) ?
The answer to inverse oflaplace-(1.25)/(s+2) is -1.25e^{-2t}