What is the integral of 1/(4\sqrt[4]{x^3)} ?

The integral of 1/(4\sqrt[4]{x^3)} is \sqrt[4]{x}+C

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integral of 1/(4\sqrt[4]{x^3)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= \frac{1}{4} \cdot \int \frac{1}{x ^{\frac{3}{4}}} d x

Apply the Power Rule

: 4 x^{\frac{1}{4}}

= \frac{1}{4} \cdot 4 x^{\frac{1}{4}}

Simplify

Add a constant to the solution

\frac{d}{d x} ((\frac{x ^{2} + 7}{x ^{2} - 7})^{3})

\frac{d y}{d x}, x + y = 5

\frac{\partial}{\partial x} (\frac{x}{2})

\frac{s + 1}{( s ^{2} + 1 ) ^{2}}

\int_{0}^{\frac{π}{4}} 5 cos^{5} (2 x) d x

What is the integral of 1/(4\sqrt[4]{x^3)} ?
The integral of 1/(4\sqrt[4]{x^3)} is \sqrt[4]{x}+C