What is the limit as x approaches 0 of ln(x^2)2e^x+1 ?

The limit as x approaches 0 of ln(x^2)2e^x+1 is diverges

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limit as x approaches 0 of ln(x^2)2e^x+1

x \to 0 lim (ln (x^{2}) 2 e^{x} + 1)

diverges

Solution steps

x \to 0 lim (ln (x^{2}) \cdot 2 e^{x} + 1)

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (x^{2}) \cdot 2 e^{x} + 1) = - \infty

x \to 0 - lim (ln (x^{2}) \cdot 2 e^{x} + 1) = 2

Does not exist

+ 1

= diverges

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What is the limit as x approaches 0 of ln(x^2)2e^x+1 ?
The limit as x approaches 0 of ln(x^2)2e^x+1 is diverges