What is the derivative of ln^2(x-1) ?

The derivative of ln^2(x-1) is (2ln(x-1))/(x-1)

What is the first derivative of ln^2(x-1) ?

The first derivative of ln^2(x-1) is (2ln(x-1))/(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (ln^{2} (x - 1))

\frac{2 ln ( x - 1 )}{x - 1}

Solution steps

\frac{d}{d x} (ln^{2} (x - 1))

Apply the chain rule:

2 ln (x - 1) \frac{d}{d x} (ln (x - 1))

= 2 ln (x - 1) \frac{d}{d x} (ln (x - 1))

\frac{d}{d x} (ln (x - 1)) = \frac{1}{x - 1}

= 2 ln (x - 1) \frac{1}{x - 1}

Simplify

2 ln (x - 1) \frac{1}{x - 1} : \frac{2 ln ( x - 1 )}{x - 1}

= \frac{2 ln ( x - 1 )}{x - 1}

x \to + 0 lim (\frac{( 1 + x ) ^{4} - 1}{x})

\int \frac{1}{2} cos^{2} (x) d x

\frac{\partial}{\partial y} (x y + yz + z x)

\int \frac{x ^{4} - 3 x ^{2} + 7}{x ^{4}} d x

x \to 5 lim (\frac{f ( x )}{g ( x )})

What is the derivative of ln^2(x-1) ?
The derivative of ln^2(x-1) is (2ln(x-1))/(x-1)
What is the first derivative of ln^2(x-1) ?
The first derivative of ln^2(x-1) is (2ln(x-1))/(x-1)