What is the integral of (ln^3(x^2))/x ?

The integral of (ln^3(x^2))/x is 2ln^4(x)+C

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integral of (ln^3(x^2))/x

\int \frac{ln ^{3} ( x ^{2} )}{x} d x

2 ln^{4} (x) + C

Solution steps

\int \frac{ln ^{3} ( x ^{2} )}{x} d x

Simplify

\frac{ln ^{3} ( x ^{2} )}{x} : \frac{8 ln ^{3} ( x )}{x}

= \int \frac{8 ln ^{3} ( x )}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int \frac{ln ^{3} ( x )}{x} d x

Apply u-substitution

: \int u^{3} d u

= 8 \cdot \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= 8 \cdot \frac{u ^{4}}{4}

Substitute back

u = ln (x)

= 8 \cdot \frac{ln ^{4} ( x )}{4}

Simplify

8 \cdot \frac{ln ^{4} ( x )}{4} : 2 ln^{4} (x)

= 2 ln^{4} (x)

Add a constant to the solution

= 2 ln^{4} (x) + C

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What is the integral of (ln^3(x^2))/x ?
The integral of (ln^3(x^2))/x is 2ln^4(x)+C