What is the integral of 1/(cot(x)) ?

The integral of 1/(cot(x)) is -ln|cos(x)|+C

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integral of 1/(cot(x))

\int \frac{1}{cot ( x )} d x

- ln ∣ cos (x) ∣ + C

Solution steps

\int \frac{1}{cot ( x )} d x

Rewrite using trig identities

= \int \frac{sin ( x )}{cos ( x )} d x

Apply u-substitution

: \int - \frac{1}{u} d u

= \int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - ln ∣ u ∣

Substitute back

u = cos (x)

= - ln ∣ cos (x) ∣

Add a constant to the solution

= - ln ∣ cos (x) ∣ + C

g (x) = x + x^{3}

\int \frac{1 + cos ( 2 x )}{2} d x

f (x) = \frac{sec ( x ) + tan ( x )}{sec ( x ) - tan ( x )}

\frac{d}{d x} (\frac{4 x}{( x + 1 )})

\int \frac{1}{4 + 3 x ^{2}} d x

What is the integral of 1/(cot(x)) ?
The integral of 1/(cot(x)) is -ln|cos(x)|+C