What is (\partial)/(\partial x)(e^{2y^2}+4x^2) ?

The answer to (\partial)/(\partial x)(e^{2y^2}+4x^2) is 8x

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(\partial)/(\partial x)(e^{2y^2}+4x^2)

\frac{\partial}{\partial x} (e^{2 y^{2}} + 4 x^{2})

8 x

Solution steps

\frac{\partial}{\partial x} (e^{2 y^{2}} + 4 x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{2 y^{2}}) + \frac{\partial}{\partial x} (4 x^{2})

\frac{\partial}{\partial x} (e^{2 y^{2}}) = 0

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

= 0 + 8 x

Simplify

= 8 x

\int_{1}^{5} \frac{1}{( x - 4 ) ^{2}} d x

\int - 2 x cos (3 x) d x

\frac{d}{d x} ((x^{2} - 2 x)^{s i n (x)})

y^{^{'}} + 3 y = x + e^{- 2 x}

x \to \infty lim (x - 2^{x})

What is (\partial)/(\partial x)(e^{2y^2}+4x^2) ?
The answer to (\partial)/(\partial x)(e^{2y^2}+4x^2) is 8x