What is the solution for y^{''}+8y^'+9y=0 ?

The solution for y^{''}+8y^'+9y=0 is y=c_{1}e^{(-4+sqrt(7))t}+c_{2}e^{(-4-sqrt(7))t}

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y^{''}+8y^'+9y=0

y^{^{''}} + 8 y^{^{'}} + 9 y = 0

y = c_{1} e^{(- 4 + 7) t} + c_{2} e^{(- 4 - 7) t}

Solution steps

y^{''} (t) + 8 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} e^{(- 4 + 7) t} + c_{2} e^{(- 4 - 7) t}

y = c_{1} e^{(- 4 + 7) t} + c_{2} e^{(- 4 - 7) t}

\int x^{2} (2 - x) d x

x \to 1 lim (ln (1))

x \to 0 lim (5 - \frac{∣ x ∣}{x})

\int_{- π}^{π} cos (x) d x

What is the solution for y^{''}+8y^'+9y=0 ?
The solution for y^{''}+8y^'+9y=0 is y=c_{1}e^{(-4+sqrt(7))t}+c_{2}e^{(-4-sqrt(7))t}