What is (\partial)/(\partial y)(1/(y^2)) ?

The answer to (\partial)/(\partial y)(1/(y^2)) is -2/(y^3)

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(\partial)/(\partial y)(1/(y^2))

\frac{\partial}{\partial y} (\frac{1}{y ^{2}})

- \frac{2}{y ^{3}}

Solution steps

\frac{\partial}{\partial y} (\frac{1}{y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{\partial}{\partial y} (y^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 y^{- 2 - 1}

Simplify

- 2 y^{- 2 - 1} : - \frac{2}{y ^{3}}

= - \frac{2}{y ^{3}}

\frac{d y}{d x} = 12 - y

x^{- 3}

\int - π + 2 t cos (n) t d t

n = 1 \sum \infty e^{n}

\int \frac{4}{x ^{2} + 4} d x

What is (\partial)/(\partial y)(1/(y^2)) ?
The answer to (\partial)/(\partial y)(1/(y^2)) is -2/(y^3)