What is the derivative of 3x^2+2x+1 ?

The derivative of 3x^2+2x+1 is 6x+2

What is the first derivative of 3x^2+2x+1 ?

The first derivative of 3x^2+2x+1 is 6x+2

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\frac{d}{d x} (3 x^{2} + 2 x + 1)

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 6 x + 2 + 0

Simplify

= 6 x + 2

t^{2} y^{^{'}} + t y = 5

x sin (3 x)

\frac{d}{d x} (\frac{1}{e ^{x} + 1})

x \cdot ln (x)

\int \frac{x + 1}{x ^{3}} d x

What is the derivative of 3x^2+2x+1 ?
The derivative of 3x^2+2x+1 is 6x+2
What is the first derivative of 3x^2+2x+1 ?
The first derivative of 3x^2+2x+1 is 6x+2