What is the integral of (4x^3+cos(x)) ?

The integral of (4x^3+cos(x)) is x^4+sin(x)+C

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integral of (4x^3+cos(x))

\int (4 x^{3} + cos (x)) d x

x^{4} + sin (x) + C

Solution steps

\int 4 x^{3} + cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{3} d x + \int cos (x) d x

\int 4 x^{3} d x = x^{4}

\int cos (x) d x = sin (x)

= x^{4} + sin (x)

Add a constant to the solution

= x^{4} + sin (x) + C

y^{^{'}} = \frac{x ^{2} - y ^{2}}{x y}

\frac{2}{u}

\int (x^{2} - 9 x + 3) d x

\frac{\partial}{\partial x} (x y + ln (\frac{x}{y}))

\int \frac{- 16 x + 3}{( x ^{2} + 2 ) ^{2}} d x

What is the integral of (4x^3+cos(x)) ?
The integral of (4x^3+cos(x)) is x^4+sin(x)+C