What is the derivative of 2x^2-4x+5 ?

The derivative of 2x^2-4x+5 is 4x-4

What is the first derivative of 2x^2-4x+5 ?

The first derivative of 2x^2-4x+5 is 4x-4

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\frac{d}{d x} (2 x^{2} - 4 x + 5)

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 4 x - 4 + 0

Simplify

= 4 x - 4

\frac{d}{d x} (e^{x} (2 x^{4} + 3 cos (x)))

\frac{d}{d x} (- 2 x^{3} + \frac{8}{x ^{2}} - 6 x - 1)

\int - 8 x^{3} cos (5 x^{4} + 1) d x

3 e^{6 x}

\frac{\partial}{\partial x} (16 x - 4 y - 6 y x)

What is the derivative of 2x^2-4x+5 ?
The derivative of 2x^2-4x+5 is 4x-4
What is the first derivative of 2x^2-4x+5 ?
The first derivative of 2x^2-4x+5 is 4x-4