What is the derivative of f(x)=-x^2-x ?

The derivative of f(x)=-x^2-x is -2x-1

What is the first derivative of f(x)=-x^2-x ?

The first derivative of f(x)=-x^2-x is -2x-1

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derivative of

f (x) = - x^{2} - x

- 2 x - 1

Solution steps

\frac{d}{d x} (- x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= - 2 x - 1

\frac{d}{d x} ((ln (8))^{x})

\frac{\partial}{\partial x} (sin^{6} (3 x - 4 y))

\frac{d}{d y} ((4 - y)^{\frac{1}{3}})

x \to 0 lim (3 x + 5)

y^{^{'}} - \frac{6}{x} y = \frac{y ^{5}}{x ^{20}}, y (1) = 1

What is the derivative of f(x)=-x^2-x ?
The derivative of f(x)=-x^2-x is -2x-1
What is the first derivative of f(x)=-x^2-x ?
The first derivative of f(x)=-x^2-x is -2x-1