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Popular >

derivative of 18cos(θ)+9sin^2(θ)

Solution

derivative of

18 cos (θ) + 9 sin^{2} (θ)

Solution

- 18 sin (θ) + 9 sin (2 θ)

Solution steps

\frac{d}{d θ} (18 cos (θ) + 9 sin^{2} (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (18 cos (θ)) + \frac{d}{d θ} (9 sin^{2} (θ))

\frac{d}{d θ} (18 cos (θ)) = - 18 sin (θ)

\frac{d}{d θ} (9 sin^{2} (θ)) = 9 sin (2 θ)

= - 18 sin (θ) + 9 sin (2 θ)

Popular Examples

(d^2)/(dx^2)(5e^{-x^2})

\frac{d ^{2}}{d x ^{2}} (5 e^{- x^{2}})

derivative of 1/(sqrt(x)+1/(sqrt(y)))

\frac{d}{d x} (\frac{1}{x} + \frac{1}{y})

tangent of f(x)=5e^x+x,\at x=0 tangent of

f (x) = 5 e^{x} + x, at x = 0

derivative of (-e^{-x/2}x+e^{-x/2}/2)

\frac{d}{d x} (\frac{- e ^{- \frac{x}{2}} x + e ^{- \frac{x}{2}}}{2})

(dy)/(dx)=-7e^{x+y}

\frac{d y}{d x} = - 7 e^{x + y}

Frequently Asked Questions (FAQ)

What is the derivative of 18cos(θ)+9sin^2(θ) ?
The derivative of 18cos(θ)+9sin^2(θ) is -18sin(θ)+9sin(2θ)
What is the first derivative of 18cos(θ)+9sin^2(θ) ?
The first derivative of 18cos(θ)+9sin^2(θ) is -18sin(θ)+9sin(2θ)