What is (\partial)/(\partial x)(x^2+3y^3) ?

The answer to (\partial)/(\partial x)(x^2+3y^3) is 2x

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(\partial)/(\partial x)(x^2+3y^3)

\frac{\partial}{\partial x} (x^{2} + 3 y^{3})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + 3 y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (3 y^{3})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 y^{3}) = 0

= 2 x + 0

Simplify

= 2 x

\int \frac{100}{w ^{2} 25 - w ^{2}} d w

x y^{^{'}} - 2 y = 3 x^{2}

f (x) = 1 - 6 x, at x = - 1

\frac{9 x}{x}

\int \frac{x ^{2} - 2 x - 5}{( x - 1 ) ^{2} ( x ^{2} + 1 )} d x

What is (\partial)/(\partial x)(x^2+3y^3) ?
The answer to (\partial)/(\partial x)(x^2+3y^3) is 2x