What is area f(x)=12x+x^2-x^3,g(x)=0 ?

The answer to area f(x)=12x+x^2-x^3,g(x)=0 is 937/12

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area f(x)=12x+x^2-x^3,g(x)=0

area

f (x) = 12 x + x^{2} - x^{3}, g (x) = 0

\frac{937}{12}

Solution steps

Apply the area formula:

\int_{- 3}^{4} - x^{3} + x^{2} + 12 x d x

Solve

\int_{- 3}^{4} - x^{3} + x^{2} + 12 x d x : \frac{937}{12}

The area is:

= \frac{937}{12}

\frac{s - 7}{s + 3}

\frac{( x ^{2} )}{x + 7}

\frac{\partial}{\partial x} (x^{2} + y^{2} + (x + y)^{2})

\frac{\partial}{\partial x} (\frac{1}{( 1 + e ^{- x} )})

\frac{d}{d x} (lo g_{10} ((x - 3)^{2}))

What is area f(x)=12x+x^2-x^3,g(x)=0 ?
The answer to area f(x)=12x+x^2-x^3,g(x)=0 is 937/12