What is the derivative of x^2sin^2(x) ?

The derivative of x^2sin^2(x) is 2xsin^2(x)+sin(2x)x^2

What is the first derivative of x^2sin^2(x) ?

The first derivative of x^2sin^2(x) is 2xsin^2(x)+sin(2x)x^2

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\frac{d}{d x} (x^{2} sin^{2} (x))

2 x sin^{2} (x) + sin (2 x) x^{2}

Solution steps

\frac{d}{d x} (x^{2} sin^{2} (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = sin^{2} (x)

= \frac{d}{d x} (x^{2}) sin^{2} (x) + \frac{d}{d x} (sin^{2} (x)) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

= 2 x sin^{2} (x) + sin (2 x) x^{2}

\int + x^{3} sin (2 x) d x

\frac{d y}{d t} = t y^{2} + 2 y^{2}

y^{^{'}} - 3 y = 2 sin (3 x) - cos (3 x)

\int \frac{6 x + 7}{x ^{2} + 4 x + 29} d x

\frac{d}{d x} (\frac{sin ^{2} ( x )}{cos ( x )})

What is the derivative of x^2sin^2(x) ?
The derivative of x^2sin^2(x) is 2xsin^2(x)+sin(2x)x^2
What is the first derivative of x^2sin^2(x) ?
The first derivative of x^2sin^2(x) is 2xsin^2(x)+sin(2x)x^2