What is area y=2x^2,y=2x+6,x=-2 ?

The answer to area y=2x^2,y=2x+6,x=-2 is 10sqrt(13)+(-21sqrt(13)+31)/6-11

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area y=2x^2,y=2x+6,x=-2

area

y = 2 x^{2}, y = 2 x + 6, x = - 2

1013 + \frac{- 21 13 + 31}{6} - 11

Decimal Notation

17.60274 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{\frac{1 + 13}{2}} 2 x^{2} - (2 x + 6) d x

Solve

\int_{- 2}^{\frac{1 + 13}{2}} 2 x^{2} - (2 x + 6) d x : 1013 + \frac{- 21 13 + 31}{6} - 11

The area is:

= 1013 + \frac{- 21 13 + 31}{6} - 11

f (x) = (3 x - 2)^{2} (x^{5} - x^{2})^{3}

x^{2} - 3 x, 3 x + 7

x \to - 4 lim ((x - 4)^{2} + 2)

9 x^{3} + 7^{x} + 20

\int \frac{u}{( u - 1 ) ^{2}} d u

What is area y=2x^2,y=2x+6,x=-2 ?
The answer to area y=2x^2,y=2x+6,x=-2 is 10sqrt(13)+(-21sqrt(13)+31)/6-11