What is (\partial)/(\partial x)(x^2-3xy) ?

The answer to (\partial)/(\partial x)(x^2-3xy) is 2x-3y

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(\partial)/(\partial x)(x^2-3xy)

\frac{\partial}{\partial x} (x^{2} - 3 x y)

2 x - 3 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 3 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (3 x y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 x y) = 3 y

= 2 x - 3 y

x 1 - y^{2} d x = d y

x \to 0 + lim (ln (- x))

n = 0 \sum \infty \frac{n}{n ^{2} + 1} x^{n}

\int_{- 2}^{3} \frac{23}{x ^{4}} d x

\int \frac{3 x ^{2} + 2 x - 1}{4 e ^{3 x}} d x

What is (\partial)/(\partial x)(x^2-3xy) ?
The answer to (\partial)/(\partial x)(x^2-3xy) is 2x-3y