What is the limit as x approaches 1 of arctan^2(x) ?

The limit as x approaches 1 of arctan^2(x) is (pi^2)/(16)

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limit as x approaches 1 of arctan^2(x)

x \to 1 lim (arctan^{2} (x))

\frac{π ^{2}}{16}

Decimal Notation

0.61685 \dots

Solution steps

x \to 1 lim (arctan^{2} (x))

Plug in the value

x = 1

= arctan^{2} (1)

Simplify

arctan^{2} (1) : \frac{π ^{2}}{16}

= \frac{π ^{2}}{16}

\frac{\partial}{\partial x} ((sin^{2} (x)) + y)

3 t - t^{2}

\frac{d}{d x} (cos (ln (sec (e^{- 2 x}))))

f (x) = (5 x - 5) (x + 3)

\frac{d}{d x} (\frac{x}{1 + x ^{3}})

What is the limit as x approaches 1 of arctan^2(x) ?
The limit as x approaches 1 of arctan^2(x) is (pi^2)/(16)