What is the limit as x approaches 0 of (1-4x)^{8/x} ?

The limit as x approaches 0 of (1-4x)^{8/x} is 1/(e^{32)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (1-4x)^{8/x}

x \to 0 lim ((1 - 4 x)^{\frac{8}{x}})

\frac{1}{e ^{32}}

Decimal Notation

1.26642 E - 14

Solution steps

x \to 0 lim ((1 - 4 x)^{\frac{8}{x}})

Apply exponent rules

= x \to 0 lim (e^{\frac{8}{x} l n (1 - 4 x)})

Apply the Limit Chain Rule:

\frac{1}{e ^{32}}

= \frac{1}{e ^{32}}

x \to 4 lim (\frac{1}{2 + x})

y = sin^{2} (e^{s i n^{2} (t)})

\int cos (2 x) e^{- x} d x

\int \frac{3 x}{x + 4} d x

\int_{0}^{t} - 5 e^{s} sin (t - s) d s

What is the limit as x approaches 0 of (1-4x)^{8/x} ?
The limit as x approaches 0 of (1-4x)^{8/x} is 1/(e^{32)}