What is area 2sin(x),4cos(x),[0,0.6pi] ?

The answer to area 2sin(x),4cos(x),[0,0.6pi] is 3.75807…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 2sin(x),4cos(x),[0,0.6pi]

area

2 sin (x), 4 cos (x), [0, 0.6 π]

3.75807 \dots

Solution steps

Apply the area formula:

\int_{0}^{0.6 π} ∣ 2 sin (x) - 4 cos (x) ∣ d x

Solve

\int_{0}^{0.6 π} ∣ 2 sin (x) - 4 cos (x) ∣ d x : 3.75807 \dots

The area is:

= 3.75807 \dots

\frac{d}{d x} ((x^{5} - x^{3} + 3)^{4})

3 y^{^{'}} + x y = 5 x

\frac{d}{d x} (x^{x^{5}})

\int (- 3 e^{x} + \frac{4}{x}) d x

\int_{7}^{8} e^{7 - x} d x

What is area 2sin(x),4cos(x),[0,0.6pi] ?
The answer to area 2sin(x),4cos(x),[0,0.6pi] is 3.75807…